How much heat is gained (in Joules) by the water where a chemical reaction takes place in 100 mL aqueous solution and has a temperature increase of 10 C?
q = mass x specific heat H2O x (delta T).
I fyou use 4.184 J/g*C for specific heat H2O then q will be in joules.
To calculate the amount of heat gained by the water in this chemical reaction, you need to use the equation:
q = m * c * ΔT
Where:
q is the heat gained (in Joules),
m is the mass of the water (in grams),
c is the specific heat capacity of water (4.18 J/g°C),
ΔT is the change in temperature (in °C).
To find the mass of water, you need to multiply the volume by its density. The density of water is approximately 1 gram per milliliter.
m = V * ρ
Where:
m is the mass of water (in grams),
V is the volume of water (in milliliters),
ρ is the density of water (1 g/mL).
Given that the volume of water is 100 mL:
m = 100 mL * 1 g/mL
m = 100 grams
Now you have the mass of the water, therefore you can calculate the heat gained in the reaction:
q = 100 g * 4.18 J/g°C * 10°C
q = 4180 J
Therefore, the water gains 4180 Joules of heat during the chemical reaction.