Hi. Can I get some help plz?
What is the mass of water that results from combining 2.0 g of hydrogen with 16.0g of oxygen?
A. 14.0 g
B. 16.0g
C.18.0 g
D. 20.0g
Thank you for your help and time :)
2.0 + 16.0 = 18.0
It's C.
Thx
Of course! I'd be happy to help you with your question.
To find the mass of water that results from combining hydrogen and oxygen, we need to determine the chemical equation for the reaction and then use stoichiometry to calculate the resulting mass.
The chemical equation for the combination of hydrogen and oxygen to form water is:
2H₂ + O₂ → 2H₂O
From the equation, we can see that it takes a ratio of 2 moles of hydrogen to 1 mole of oxygen to form 2 moles of water.
To calculate the mass of water formed, we can use the molar masses of hydrogen (H) and oxygen (O) to convert the given masses into moles.
The molar mass of hydrogen (H) is approximately 1.008 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol.
For 2.0 g of hydrogen, we can calculate the number of moles using the formula:
moles = mass / molar mass
moles of hydrogen = 2.0 g / 1.008 g/mol = 1.984 moles
For 16.0 g of oxygen, we can calculate the number of moles using the same formula:
moles of oxygen = 16.0 g / 16.00 g/mol = 1.000 moles
Since the ratio of hydrogen to oxygen in the equation is 2:1, we can determine that the limiting reactant is oxygen. This means that oxygen will be completely used up in the reaction, and the amount of water formed will be determined by the amount of oxygen present.
Using the stoichiometry of the equation, we can determine that for every 1 mole of oxygen, 2 moles of water are formed. Therefore, with 1.000 moles of oxygen, we can expect the formation of 2.000 moles of water.
Finally, to calculate the mass of water formed, we can multiply the number of moles of water formed by its molar mass:
mass of water = moles of water * molar mass of water
mass of water = 2.000 moles * (2 * molar mass of hydrogen + molar mass of oxygen)
mass of water = 2.000 moles * (2 * 1.008 g/mol + 16.00 g/mol)
mass of water = 2.000 moles * (2.016 g/mol + 16.00 g/mol)
mass of water = 2.000 moles * 18.016 g/mol
mass of water = 36.032 g
Therefore, the mass of water that results from combining 2.0 g of hydrogen with 16.0 g of oxygen is approximately 36.032 g.
None of the given answer choices exactly match this calculated value. However, the closest option is 18.0 g, which is represented by choice C.