algebra readiness benchmark #2 mrs. makowsky.
1.) The area of a rectangle is 7.7682 x 10(4) cm(2) and the width is 2.42 x 10(2) cm. What is the length?
a. 3.21 x 10(2)
b. 3.21 x 10(6)
c. 1.88 x 10(8)
d. 1.88 x 10(6)
Plz help asap cause I have no clue.
I also need help w the other 35 questions if you know them lol
Online "^" is used to indicate an exponent, e.g., x^2 = x squared.
Online, “*” is used to indicate multiplication to avoid confusion with “x” as an unknown.
Area = length * width
7.7682*10^4 = Length * 2.42*10^2
(7.7682*10^4)/(2.42*10^2) = Length
When multiplying/dividing, add/subtract exponents respectively.
Solve for length.
so is the answer a. then?
Without doing all of the division, definitely it is 10^2.
The correct answer is 3.21 x 10^2. I just finished the test
To find the length of the rectangle, you need to use the formula for the area of a rectangle: Area = length x width.
In this case, you are given the area of the rectangle, which is 7.7682 x 10(4) cm(2), and the width, which is 2.42 x 10(2) cm.
To find the length, divide the area by the width using scientific notation.
7.7682 x 10(4) cm(2) / 2.42 x 10(2) cm
To divide numbers in scientific notation, divide the coefficients (the numbers before the "x 10") and subtract the exponents (the numbers in parentheses).
7.7682 / 2.42 = 3.21
10(4) / 10(2) = 10(4 - 2) = 10(2)
So, the length of the rectangle is 3.21 x 10(2) cm.
Therefore, the correct answer is option a. 3.21 x 10(2).