two buses leave a bus station and travel in opposite directions from that same starting point. if the speed of the other is twice the speed of the other and they are 240km apart at the end of one hour, what is the speed of each bus?
V1 = X km/h.
V2 = 2x km/h.
d1 = V1 * t = X * 1 = X km.
d2 = V2 * t = 2x * 1 = 2x km.
d2 - d1 = 2x - (-x) = 240 km.
2x + x = 240,
X = 80 km = d1.
d2 = 2x = 2 * 80 = 160 km.
d1 = V1 * t = 80,
V1 * 1 = 80,
V1 = 80 km/h.
d2 = V2 * t = 160,
V2 * 1 = 160,
V2 = 160 km/h.
V1 = X km/h.
V2 = 2x km/h.
d1 = V1 * t = x * 1 = X km.
d2 = V2 * t = 2x * 1 = 2x km.
d2 - d1 = 2x - x = 240.
X = 240 km. = d1.
2x = 2 * 240 = 480 km. = d2.
d1 = V1 * t = 240,
V1 * 1 = 240,
V1 = 240 km/h.
d2 = V2 * t = 480,
V2 * 1 = 480,
V2 = 480 km/h.
Was it 2 buses or 2 planes?
The speed is too high for a bus.
solve it for me
Rate of one --- x
rate of the other --- 2x
They both drove for 1 hour, so their distance are 1(x) and 1(2x) km
connect the dots for me.
To find the speed of each bus, let's assume the speed of one bus is "x" km/h. Since the other bus is traveling twice as fast, its speed will be "2x" km/h.
Now, we know that the total distance traveled by both buses in one hour is 240km. Since they are traveling in opposite directions, we can add their distances to get the total distance:
Distance traveled by the first bus = x km/h * 1 hour = x km
Distance traveled by the second bus = 2x km/h * 1 hour = 2x km
Adding these distances, we have:
x km + 2x km = 240km
Combining like terms:
3x km = 240km
To find "x," divide both sides of the equation by 3:
x = 240km / 3
x = 80km/h
Thus, the speed of the first bus is 80 km/h, and the speed of the second bus is twice that, which is 160 km/h.