The following chemical reaction takes place in aqueous solution:
MnBr2(aq) + 2KOH (aq) → Mn(OH)2 (s) + 2KBr (aq)
Write the net ionic equation for this reaction.
1. Convert to full ionic equation. Mn(OH)2 is the only solid that does not dissociate.
2. Cancel ions that are the same on both sides/
3. What's left is the net ionic equation.
Post your work if you get stuck.
I ended up with
Mn^2+(aq)+2OH- =Mn(OH)2
Is that right?
To write the net ionic equation, we need to exclude any spectator ions from the complete ionic equation.
The complete ionic equation for the reaction is:
Mn2+(aq) + 2Br-(aq) + 2K+(aq) + 2OH-(aq) → Mn(OH)2(s) + 2K+(aq) + 2Br-(aq)
The spectator ions in this reaction are K+ and Br-. These ions are present on both the reactant and product sides of the equation and do not participate in the actual chemical reaction.
The net ionic equation is obtained by removing the spectator ions:
Mn2+(aq) + 2OH-(aq) → Mn(OH)2(s)
Therefore, the net ionic equation for this reaction is Mn2+(aq) + 2OH-(aq) → Mn(OH)2(s)
To write the net ionic equation for a reaction, we need to start by writing the balanced molecular equation. The molecular equation shows the complete chemical formula of all the reactants and products.
The balanced molecular equation for the given reaction is:
MnBr2(aq) + 2KOH(aq) → Mn(OH)2(s) + 2KBr(aq)
Next, we need to determine the physical states of the reactants and products. (s) indicates a solid, (l) indicates a liquid, (g) indicates a gas, and (aq) indicates aqueous (dissolved in water).
The reactants MnBr2 and KOH are both aqueous, indicated by (aq). The product Mn(OH)2 is a solid, indicated by (s), and KBr is also aqueous, indicated by (aq).
Now, we can write the complete ionic equation by representing all the strong electrolytes (aqueous substances) as their dissociated ions.
Mn2+(aq) + 2Br-(aq) + 2K+(aq) + 2OH-(aq) → Mn(OH)2(s) + 2K+(aq) + 2Br-(aq)
Finally, we need to write the net ionic equation by eliminating the spectator ions. Spectator ions are ions that appear on both sides of the equation and do not participate in the actual chemical reaction.
In this case, the spectator ions are 2K+ and 2Br-. These ions are present on both sides of the equation and do not undergo any change. Therefore, we can eliminate them from the equation. The remaining ions that participate in the reaction are Mn2+ and 2OH-.
The net ionic equation for the given reaction is:
Mn2+(aq) + 2OH-(aq) → Mn(OH)2(s)
That's how you write the net ionic equation for the given chemical reaction!