A race car is moving with a velocity of 144 kilometers/hour. The driver applies the brakes, and the car comes to a halt in 12.0 seconds. What is the average acceleration of the car during those 12.0 seconds?
what grade are you in
11th
thx but the awnser for me to choose from are:
A.
–12.0 meters/second2
B.
–3.3 meters/second2
C.
3.3 meters/second2
D.
10.3 meters/second2
thank tyou
You're welcome :)
ohh, bye i'm in 8th- sorry
I would say the answer is A because 144 is 12×12 or 12 squared (12^2)
no u
To find the average acceleration of the car, we need to use the formula:
acceleration = (final velocity - initial velocity) / time
In this case, the initial velocity of the car is 144 kilometers/hour and the final velocity is 0 (since the car comes to a halt).
First, let's convert the initial velocity from kilometers/hour to meters/second. To do this, we need to multiply it by the conversion factor 1000 meters / 1 kilometer and then divide it by 3600 seconds / 1 hour:
Initial velocity = 144 kilometers/hour * (1000 meters / 1 kilometer) / (3600 seconds / 1 hour)
= (144 * 1000) / 3600 meters/second
= 40 meters/second
Now, we can calculate the acceleration:
Acceleration = (final velocity - initial velocity) / time
= (0 - 40) meters/second / 12.0 seconds
= -40 meters/second / 12.0 seconds
= -3.33 meters/second^2
Therefore, the average acceleration of the car during those 12.0 seconds is -3.33 meters/second^2.
I'll help you Jason.
the formula is a = F / m
Force (F) = 12 and Mass (m) = 144,
a = 12/144
a = 0.08
( A is Acceleration)
You're welcome!