Calculate the mass of Na2C2O4 needed to react with 30mL of 0.050 M KMnO4
please help! i know i have 30ml of 0.050 mol kmno4 but i dont know what this means,
5Na2C2O4 + 2KMnO4 + 8H2SO4 ==> 8H2O + 10CO2 + 2MnSO4 + K2SO4 + 5Na2SO4
Check that question to make sure it is balanced correctly.
mols KMnO4 = mols x L = ?
From the equation you see 2 mols KMnO4 = 5 mols Na2C2O4. From this convert mols KMnO4 you have to mols Na2C2O4.
Then convert mols Na2C2O4 to grams. g = mols x molar mass = ?
Post your work if you get stuck.
To calculate the mass of Na2C2O4 needed to react with 30 mL of 0.050 M KMnO4, you need to follow these steps:
Step 1: Understand the given information.
- You know that you have 30 mL of a solution with a concentration of 0.050 M KMnO4.
Step 2: Determine the moles of KMnO4.
- To find the number of moles, you can use the formula: moles = concentration (M) × volume (L).
- Convert the given volume of 30 mL to liters: 30 mL ÷ 1000 = 0.030 L.
- Plug the values into the formula: moles = 0.050 M × 0.030 L = 0.0015 moles.
Step 3: Determine the stoichiometry between KMnO4 and Na2C2O4.
- The balanced chemical equation shows the stoichiometry between the reactants and products.
- The equation for the reaction between KMnO4 and Na2C2O4 is as follows:
2 KMnO4 + 5 Na2C2O4 + 3 H2SO4 → K2SO4 + 2 MnSO4 + 10 CO2 + 8 H2O.
This equation tells us that 2 moles of KMnO4 react with 5 moles of Na2C2O4.
Step 4: Calculate the moles and mass of Na2C2O4 needed.
- Since the stoichiometry ratio is 5 moles of Na2C2O4 per 2 moles of KMnO4, you can set up a ratio:
(0.0015 moles of Na2C2O4 / 2 moles of KMnO4) × 5 moles of Na2C2O4 = 0.00375 moles of Na2C2O4.
- Finally, use the formula for calculating mass: mass = moles × molar mass.
- The molar mass of Na2C2O4 is:
2(Na) + 2(C) + 4(O) = 46 g/mol + 24 g/mol + (4 × 16 g/mol) = 134 g/mol.
- Substitute the values into the formula: mass = 0.00375 moles × 134 g/mol = 0.5025 grams.
Therefore, you would need approximately 0.5025 grams of Na2C2O4 to react completely with 30 mL of 0.050 M KMnO4.