How many grams of hydrogen are there in 140g of ethylene (C2H4) gas?
To determine the number of grams of hydrogen in 140g of ethylene (C2H4) gas, we need to calculate the molar mass of hydrogen and the molar mass of ethylene.
The molar mass of hydrogen (H) is approximately 1 g/mol.
The molar mass of ethylene (C2H4) can be calculated as follows:
2 mol of carbon (C) has a molar mass of 12 g/mol, so 2 x 12 = 24 g/mol.
4 mol of hydrogen (H) has a molar mass of 1 g/mol, so 4 x 1 = 4 g/mol.
Therefore, the molar mass of ethylene (C2H4) is 24 g/mol + 4 g/mol = 28 g/mol.
Now we can calculate the number of moles of ethylene in 140g by dividing the given mass by the molar mass of ethylene:
140 g / 28 g/mol = 5 mol
Since there are 4 moles of hydrogen in 1 mole of ethylene, we can calculate the number of moles of hydrogen:
4 moles H/ 1 mole C2H4 x 5 mol C2H4 = 20 moles H
Finally, we can determine the mass of hydrogen by multiplying the number of moles by the molar mass of hydrogen:
20 mole H x 1 g/mol H = 20 g of hydrogen.
Therefore, there are 20 grams of hydrogen in 140 grams of ethylene (C2H4) gas.
To determine the number of grams of hydrogen in 140g of ethylene (C2H4) gas, we first need to calculate the molecular weight of ethylene.
The molecular weight of C2H4 can be determined by adding up the atomic weights of each element.
C (carbon) has an atomic weight of 12.01 g/mol, and there are 2 carbon atoms in ethylene.
H (hydrogen) has an atomic weight of 1.01 g/mol, and there are 4 hydrogen atoms in ethylene.
Therefore, the molecular weight of ethylene is:
(2 * 12.01 g/mol) + (4 * 1.01 g/mol) = 24.02 g/mol + 4.04 g/mol = 28.06 g/mol
Now, we can calculate the number of moles of ethylene:
140 g / 28.06 g/mol = 4.98 mol
Since there are 4 hydrogen atoms in one mole of ethylene, the number of moles of hydrogen in 4.98 mol of ethylene is:
4 * 4.98 mol = 19.92 mol
To calculate the mass of hydrogen, we multiply the number of moles by the atomic weight of hydrogen:
19.92 mol * 1.01 g/mol = 20.11 g
Therefore, there are approximately 20.11 grams of hydrogen in 140g of ethylene gas.
140g of ethylene*(1 mole/28.05 g)=moles of ethylene
moles of ethylene*(4 moles of H/1 mole of ethylene)*(1.008g/mole)=????
Use the appropriate number of significant figures.