Solve
q+12-2(q-22) > 0
Can I get help on how to solve this? I'm really stuck on it
q+12-2(q-22) > 0
q + 12 - 2q + 44 > 0
-q > -56
q < 56
for those still confused,
q + 12 - 2 (q - 22) >0
first you are going to subtract 12 from the equation, (which is just pretty much just subtracting 12 from 0. the equation will now be this,
q - 2 (q - 22) > -12
now solve the parenthesis. multiply the -2 by the q and 22 (-2q + 44)
your equation will now look like this,
q - 2q + 44 > -12
now combine like terms, q - 2q = -q the equation is now,
-q + 44 > -12
subtract 44 from the equation, -12 - 44 = -56
now we have -q > -56
now reverse the inequality
final answer: q < 56
hope this helps!
dis right?
Getting Rid of Negative Variables (Simplifying Math)
by Eric Buffington
0:54 explains the last bit lads
q<56
To solve the inequality q + 12 - 2(q - 22) > 0, we can follow these steps:
Step 1: Simplify the equation.
Start by distributing the -2 to the terms inside the parentheses.
q + 12 - 2q + 44 > 0
Step 2: Combine like terms.
Combine the q terms.
-q + 12 + 44 > 0
(12 + 44) - q > 0
56 - q > 0
Step 3: Isolate q.
To isolate q, we need to move 56 to the other side of the inequality.
-q > -56
Step 4: Solve for q.
To get q by itself, we multiply both sides of the inequality by -1. Remember that when multiplying or dividing by a negative number, the inequality sign must be flipped.
q < 56
Step 5: Write the solution.
The solution to the inequality q + 12 - 2(q - 22) > 0 is q < 56.