A 63 kg rock with a volume of 42 L is completely submerged in water. The density of water is 1 kg/L.
a.) What volume of water is displaced by the rock?
L
b.) What is the buoyant force on the rock?
N
a. 42 L. Because it is completely submerged.
b. 1kg/L * 42L = 42 kg. = Wt. of water displaced = Buoyant force.
To find the volume of water displaced by the rock, we need to use the concept of buoyancy and Archimedes' principle. According to Archimedes' principle, an object submerged in a fluid experiences an upward buoyant force equal to the weight of the fluid it displaces.
a.) To determine the volume of water displaced by the rock, we need to find the weight of the rock. The weight can be calculated using the formula:
Weight = Mass × Acceleration due to gravity
Given that the rock has a mass of 63 kg, we can calculate its weight:
Weight = 63 kg × 9.8 m/s^2 (acceleration due to gravity) = 617.4 N
Since the density of water is given as 1 kg/L, we know that 1 L of water weighs 1 kg. Therefore, the weight of the water displaced by the rock is equal to 617.4 N.
Now, we can calculate the volume of water displaced using the formula:
Volume of water displaced = Weight of water displaced / Density of water
Volume of water displaced = 617.4 N / 1 kg/L = 617.4 L
Therefore, the volume of water displaced by the rock is 617.4 L.
b.) The buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced.
Buoyant force = Weight of water displaced = 617.4 N
Therefore, the buoyant force on the rock is 617.4 N.