Point A(6,-2) is reflected over the x-axis. Write the coordinates of A'.
The anwser is (6,2) but I don't understand it can someone explain?
It starts 2 units below the x axis
It therefore shoots up to the other side of the x axis to 2 units above
Old y = - 2
New y = +2
Since it reflects over x axis, it does not move right or left. x does not change and is still +6
To find the coordinates of the point A' after reflecting point A(6, -2) over the x-axis, we need to perform a transformation.
When a point is reflected over the x-axis, the y-coordinate changes sign, while the x-coordinate remains the same.
In this case, the x-coordinate of point A is 6. Since there is no change in the x-coordinate during the reflection over the x-axis, the x-coordinate of A' will also be 6.
Now, for the y-coordinate of point A, which is -2. When we reflect this point over the x-axis, the sign of the y-coordinate will change. The negative sign indicates that the point lies below the x-axis. After the reflection, the new y-coordinate will be positive and the point will lie above the x-axis. Therefore, the y-coordinate of A' will be 2.
So, the coordinates of A' will be (6, 2).