If a car accelerates at a constant rate of -5.60m/s^2 while braking, the velocity changes from +12.5m/s to +3.30m/s.
a) determine the amount of time it takes to do this.
b) determine how far the car travels during the time.
a) (velocity change) / acceleration = time
... (3.30 m/s / 12.5 m/s) / (-5.60 m/s^2) = t
b) distance = average velocity * time
... d = [(12.5 m/s + 3.30 m/s) / 2] * t