5.85 g of sodium chloride dissolved in 250 ml of solution . calculate molarity of the solution

To calculate the molarity of a solution, you need to know the moles of solute and the volume in liters.

First, let's convert the mass of sodium chloride to moles using its molar mass.

The molar mass of sodium chloride (NaCl) is 58.44 g/mol.

To find the moles, divide the given mass by the molar mass:

moles of NaCl = mass / molar mass
= 5.85 g / 58.44 g/mol
= 0.1 mol

Next, convert the volume from milliliters to liters:

volume = 250 ml ÷ 1000
= 0.25 L

Now you have the moles of solute (0.1 mol) and the volume in liters (0.25 L), you can calculate the molarity:

molarity (M) = moles of solute / volume of solution
= 0.1 mol / 0.25 L
= 0.4 M

Therefore, the molarity of the solution is 0.4 M.

To calculate the molarity of a solution, you need to know the number of moles of solute and the volume of the solution.

First, we need to convert the mass of sodium chloride (in grams) to moles. To do this, divide the mass by the molar mass of sodium chloride (NaCl), which is 58.44 g/mol.

Number of moles of NaCl = mass of NaCl (g) / molar mass of NaCl

Number of moles of NaCl = 5.85 g / 58.44 g/mol
Number of moles of NaCl = 0.1 mol

Next, we need to convert the given volume of the solution (250 mL) to liters since molarity is expressed in moles per liter.

Volume of solution = 250 mL = 250 / 1000 = 0.25 L

Finally, we can calculate the molarity by dividing the number of moles of solute by the volume of the solution in liters.

Molarity of the solution = Number of moles of NaCl / Volume of solution

Molarity of the solution = 0.1 mol / 0.25 L

Molarity of the solution = 0.4 mol/L

Therefore, the molarity of the solution is 0.4 mol/L.

Na = 23 g/mol

Cl = 35.5 g/mol
so
NaCl = 58.5 g/mol
so we have
5.85/58.5 = 0.1 mols of NaCl in 0.25 liters
so we would have 0.1 * 4 = 0.4 mols in 1.00 liter