A ball is projected horizontally from top of a hill with a velocity of 30m/s.If it reaches the ground 5 seconds later, calculate the height of the hill,take g=10 metres per second square.
h = 1/2 g t^2
horizontal velocity is not a factor
I need the formula
No
A ball
To calculate the height of the hill, we can use the equation of motion for vertical motion:
h = u*t + (1/2)*g*t^2
where:
- h is the height of the hill (which is what we want to find),
- u is the initial vertical velocity of the ball (which is 0 because the ball is projected horizontally),
- t is the time it takes for the ball to reach the ground (which is given as 5 seconds), and
- g is the acceleration due to gravity (given as 10 m/s^2).
Substituting the given values into the equation, we have:
h = 0*5 + (1/2)*10*(5)^2
h = 0 + (1/2)*10*25
h = 0 + 125
h = 125 meters
Therefore, the height of the hill is 125 meters.