The first and the last term of an AP are 6.7 and 17.1 respectively. If there are 14 terms in the sequence find the common difference
Solve the question fully from the beginning
The 14th term is 13 terms after the 1st.
So, the common difference is
formular(first term-last term / the number of terms in the squence)
(17.1-6.7)/13 = 0.8
I don't understand how you solve the question
The 14th term is 13 terms after the 1st.
So, the common difference is
(17.1-6.7)/13 = 0.8
Pls how do i solve it
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Correct
Solve it fully
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