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a baseball is hit straight up from a height of 6 feet with an initial velocity of90 feet per second. given the equations=-16t^2 +v0t + s0, that models the height of the ball,s, as a function of time ,t where the initial height of the ball is s0 and the initial velocity is v0. How high is the ball after 4 seconds?
s=-16(4)^2 +90(4)+6
s=-256++366 +6
s=110
110 feet after 4 seconds
is that correct?
Thank you for checking my work

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sara

  1. Yes, agree

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    Damon

  2. thank you!

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    sara

  4. You are welcome :)

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    Damon

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