Algebra

Ok, I am horrible at math so I am going to need someone's help.....
1. Solve.
|x+3|<5
a. -8<x<2 ****
b. -2<x<8
c.3<x<5
d.-3<x<5

2. Solve.
|-3n| - 2 = 4
a. 2 or -2 ****
b. 3 or -3
c. 4 or -4
d. 6 or -6

3. Solve.
|f| - 2/3=5/6
a. 5/6 or -5/6
b. 2/3 or -2/3
c. 1 1/2 or -1 1/2
d. no solution

4. Solve.
-2 |x - 5|≤ -10
a. x ≤ -5 or x ≥ 5
b. -5 ≤ x ≤ 5
c. x ≤ 0 or x ≥ 10
d. -10 ≤ x ≤ 10

5. The ideal circumference of a woman's basketball is 28.75 in. The actual circumference may vary from the ideal by at most 0.25 in. What are the acceptable circumferences for a woman's basketball? Let the variable,c, represent circumference.
a. c ≤ 28.5 in. or c ≥ 29 in.
b. c < 28.5 in. or c > 29 in.
c. 28.5 in. ≤ c ≤ 29 in.
d. 28.5 < c < 29 in.

Please help!!

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  1. 1. agree
    2. agree
    3. hint f - 4/6 = 5/6 and -f - 4/6 = 5/6

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  2. -2 |x - 5|≤ -10
    |x-5| >= 5
    That is, x must be at least 5 away from 5
    x ≤ 0 or x ≥ 10
    or, algebraically,
    (x-5)^2 >= 25
    x^2 - 10x + 25 >= 25
    x^2-10x >= 0
    x(x-10) >= 0
    so, either both are positive (x >= 10)
    or both are negative (x <= 0)

    28.75 - 0.25 <= c <= 28.75 + 0.25
    28.5 <= c <= 29.0

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  3. 4.
    -2 |x - 5|≤ -10
    |x-5| >/= 5
    ends
    (x-5) = 5 is x = 10
    -(x-5) = 5 is -x = 0
    c

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  4. circumference between AND including the end points

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  5. Answer:
    1: A
    2: A
    3: C
    4: C
    5: C

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  6. playfun is correct i got a 100 !

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