A manufacturing company finds that they can sell 300 items at $3.50 per item and 500 items at $1.50 per item . If the relationship between the number of items sold x and the price per item p is a linear one :
Find a formula that gives x in terms of p(x)-100+b I need help find out the b in slope intercept form.
Now use the formula to find the number of items they will if the price per item is $2.50.
(300,3.5) (500,1.5)
P=mx+b
m=y_2-y_1/x_2-x_1=300-500/3.5-1.5=200/-2 -100
P=-100x+b
Please help me find b and maybe start part b for me. Thanks
You asked the same question 2 days ago and I gave you a good start.
Did you not continue ?
https://www.jiskha.com/questions/1775681/A-manufacturing-company-finds-that-they-can-sell-300-items-at-3-50-per-item-and
yes i did not continue because help finding b.
To find the value of b in slope-intercept form (y = mx + b), we can use one of the given data points. Let's use the point (300, 3.5).
We have the equation: p = -100x + b
Substituting in the values from the point (300, 3.5):
3.5 = -100(300) + b
Multiplying -100 by 300 and rearranging the equation:
3.5 = -30000 + b
To solve for b, add 30000 to both sides:
b = 30000 + 3.5
b = 30003.5
So, the value of b is 30003.5.
Now, let's move on to part b and find the number of items they will sell if the price per item is $2.50.
We want to find x when p = $2.50.
Using the equation p = -100x + b and substituting the values for p and b:
2.50 = -100x + 30003.5
Rearranging the equation:
-100x = 2.50 - 30003.5
Adding 30003.5 to both sides:
-100x = -30001
Dividing both sides by -100:
x = -30001 / -100
x = 300.01
Therefore, if the price per item is $2.50, the number of items sold will be approximately 300.01.