a force 150N is inclined at 50 to the horizontal direction find it component in the horizontal and vertical directions
Fx = 150*Cos50 =
Fy = 150*sin50 =
To find the components of force, you can use trigonometry. In this case, the force is inclined at an angle of 50° to the horizontal direction.
The horizontal component, denoted as Fx, can be found using the cosine function:
Fx = Force × cos(angle)
Plugging in the values:
Fx = 150 N × cos(50°)
Fx = 150 N × 0.6428
Fx ≈ 96.42 N
So, the horizontal component of the force is approximately 96.42 N.
The vertical component, denoted as Fy, can be found using the sine function:
Fy = Force × sin(angle)
Plugging in the values:
Fy = 150 N × sin(50°)
Fy = 150 N × 0.7660
Fy ≈ 114.90 N
So, the vertical component of the force is approximately 114.90 N.
To find the horizontal and vertical components of a force, we need to use trigonometry. In this case, we have a force of 150N inclined at 50 degrees to the horizontal direction.
To find the horizontal component of the force, we need to find the cosine of the angle. The horizontal component (F_x) can be calculated using the formula:
F_x = F * cos(theta)
Where F is the magnitude of the force, and theta is the angle between the force and the horizontal direction.
Plugging in the values, we have:
F_x = 150N * cos(50°)
Now, we need to find the vertical component of the force. We can use the sine of the angle to find it. The vertical component (F_y) can be calculated using the formula:
F_y = F * sin(theta)
Again, plugging in the values, we have:
F_y = 150N * sin(50°)
Calculating these values gives us:
F_x = 150N * cos(50°) ≈ 96.21 N (rounded to two decimal places)
F_y = 150N * sin(50°) ≈ 114.83 N (rounded to two decimal places)
Therefore, the horizontal component of the force is approximately 96.21 N and the vertical component of the force is approximately 114.83 N.