the height above ground level i

n meters of a missile launched vertically ,is given by h(t)=-16t3+100t .at what time is the missile 72mabove ground level ? (t is time in seconds)

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  1. just solve for t in

    -16t^2 + 100t = 72

    This assumes a normal rocket trajectory under constant gravity. Not sure where a cubic function would work.

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  2. get vertex by complete square method

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  3. to use derivatives

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  4. I havenot respond!!!! But the question is more complex for me..

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  5. I do'nt Know

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  6. Math

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