the first term of an ap is -1 and the common difference is 0.5,the 6th term is what?
-1 + (5 * 0.5)
1.5
If the first term of AP is 1 and the common difference is 0.5 the 6th term is
Tn=a+{n-1}d
T6=1+(6-1)0.5
T6= 1+(5*0.5)
T6=3.5
Fine the value of P and Q is arithmetic progression 12,P, Q18
If the first term of a p is 1 and common difference is 0.5 the 6 term is
If the 6th term of an arithmetic progression is 11 and the first term is what
it good but I have more questions
To find the 6th term of an arithmetic progression (AP), we need to use the formula for the nth term of an AP:
nth term = first term + (n-1) * common difference
Given that the first term (a) of the AP is -1 and the common difference (d) is 0.5, we can substitute these values into the formula:
6th term = -1 + (6-1) * 0.5
Simplifying this expression:
6th term = -1 + 5 * 0.5
Multiplying:
6th term = -1 + 2.5
Adding:
6th term = 1.5
Therefore, the 6th term of the arithmetic progression is 1.5.