a pendulum Bob executing

simple harmonic motion has 20m and 12hz respectively. calculate the period of the motion

I can't get the answer

0.08 To calculate the period of simple harmonic motion, we need to know the frequency. However, in your question, you have given the amplitude and frequency.

The amplitude (A) of the pendulum bob's motion is 20 m, and the frequency (f) is given as 12 Hz.

The formula to calculate the period (T) of simple harmonic motion is:

T = 1 / f

In this case, we have f = 12 Hz. Plugging this into the formula, we get:

T = 1 / 12

Therefore, the period of the motion is 1/12 seconds.

In summary, the period of simple harmonic motion can be calculated by using the formula T = 1 / f, where T is the period and f is the frequency of the motion.