in an examination 3 candidates passed chemistry 29 passed physics and 3 failed both subjects. if 50 candidates sat for the examination, how many if them passed chemistry only
of the 50, 47 passed something
but you only list 3+29=32 as having passed something
Now, maybe you meant 30 passed chemistry. If so, then if x passed both, then
30+29-x = 47
x = 12
so, 30-12=18 passed only chemistry.
Well, it sounds like there's a chemistry-themed party going on here! So, let's get started with the numbers. We have a total of 50 candidates, right? Out of those, 3 failed both chemistry and physics. That means we can subtract those 3 from the total, leaving us with 47 candidates. Now, we know that 29 passed physics, so we need to subtract those 29 from the remaining 47.
So, if my calculations are correct, that means there are 18 candidates who passed chemistry only. But hey, don't worry, those 18 candidates aren't alone! They have each other for company, forming their very own exclusive chemistry club. I bet they're bonding really well!
To find out how many candidates passed chemistry only, we need to subtract the number of candidates who passed both chemistry and physics, as well as those who passed physics only, from the total number of candidates who passed chemistry.
We know that:
- 3 candidates failed both subjects.
- 29 candidates passed physics.
- There were a total of 50 candidates.
Let's solve step by step:
1. Calculate the number of candidates who passed both chemistry and physics. We know that 3 candidates failed both subjects, so the number of candidates who passed both subjects would be 50 - 3 = 47.
2. Calculate the number of candidates who passed physics only. We know from the given information that 29 candidates passed physics, so the number of candidates who passed both chemistry and physics needs to be subtracted from this number: 29 - 47 = -18. We disregard negative values in this case as it is not applicable.
3. Finally, calculate the number of candidates who passed chemistry only. Subtract the number of candidates who passed both subjects from the total number of candidates who passed chemistry: 50 - 47 = 3.
Therefore, 3 candidates passed chemistry only.
To find out how many candidates passed chemistry only, we need to subtract the number of candidates who passed both chemistry and physics, as well as the candidates who passed both subjects.
Let's break down the given information:
- Total candidates who sat for the examination = 50
- Candidates who passed chemistry = 3
- Candidates who passed physics = 29
- Candidates who failed both subjects = 3
To find the number of candidates who passed both chemistry and physics, we subtract the candidates who failed both subjects from the number of candidates who passed physics.
Candidates passing both chemistry and physics = Candidates who passed physics - Candidates failed both subjects
= 29 - 3
= 26
Now, to find the number of candidates who passed chemistry only, we subtract the candidates who passed both subjects from the total candidates who passed chemistry.
Candidates passing chemistry only = Candidates who passed chemistry - Candidates passing both chemistry and physics
= 3 - 26
= -23
In this case, we have a negative value for the number of candidates passing chemistry only, which does not make sense. It is likely that there is an error in the given information or the question itself. Please double-check the question and the values given.