Solve the equation 4x2+x+10=0
4x2+x+10=0
8 + 10 + x = 0
x = -18
4x^2 + x + 10 = 0.
Use Quadratic Formula:
X = (-1 +- sqrt(1^2 - 160))/8 = (-1 +- sqrt(-159))/8.
The quantity under the radical is negative; therefore, we have no real solution.
To solve the quadratic equation 4x^2 + x + 10 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 4, b = 1, and c = 10. Substituting these values into the quadratic formula, we get:
x = (-(1) ± √((1)^2 - 4(4)(10))) / (2(4))
x = (-1 ± √(1 - 160)) / 8
x = (-1 ± √(-159)) / 8
Since the discriminant (√(b^2 - 4ac)) is negative (which means there are no real solutions), the equation has no real solutions.