Question

A boy is pulling a load of 150N with a string inclined at an angle of 30 degrees to the horizontal.If the tension in the string is 105N, calculate the force tending to lift the load off the ground.

Answer 1

105 sin 30 = 52.5

Answer 2

Simply 105 (sin30)

=52.5

Answer 3

Sin30=opp/hyp

Sin30=x/150

Cross multiply.

X=150sin30

Therefore, x=52.5

Answer 4

If f(t)=2t3+9t2+at-b where a and b are constant,find the values of the

constant a and b Hence
(1) factorize f(t) completely
(2) State the zeros of f(t)
(3) find the remainder when f(t) is divided by (t-5)

Answer 5

I don't understand

Answer 6

Opp is x, tending to bring the load off load, remember that resolution of vectors is reversing process of finding two vectors which have the same effect of the resultant vector, so instead of finding the resultant we find the the other forces tending the to pull the resultant, we this question we represent it in the form of a right angle triangle. I hope this helps . Thank you

Answer 7

Calculate it please

Answer 8

Thanks

Answer 9

Am confused

Answer 10

Not enough explanation.

Answer 11

I don't understand

Answer 12

The answer is 52.5 N because 105 is second tension in the string and we ask to calculate the force tending to lift the load off the ground so:since it is bending it will be vertical and then the calculation will be Fx=F*sin30 and sin30 is 1\2,Fx=105*1\2 which is 52.5N