If the area of the base of Cheops pyramid is 570,025 ft squared what is the length of one of the sides of the ancient structure
42506.25
To find the length of one side of the Cheops pyramid, we can use the formula for the area of a square:
Area = side length * side length
Given that the area of the base is 570,025 ft², we can set up the equation as follows:
570,025 = side length * side length
To solve for the side length, we can take the square root of both sides of the equation:
√570,025 = √(side length * side length)
Taking the square root of both sides gives us:
side length = √570,025
Calculating the square root of 570,025 gives us:
side length ≈ 754.88 ft
Therefore, the length of one side of the Cheops pyramid is approximately 754.88 feet.
To find the length of one side of the base of the Cheops pyramid, we can use the formula for the area of a square:
Area = side length * side length
Given that the area of the base is 570,025 ft², we can set up the equation as follows:
570,025 = side length * side length
To solve for the side length, we need to take the square root of both sides of the equation:
√570,025 = √(side length * side length)
√570,025 = side length
Therefore, the length of one side of the base of the Cheops pyramid is approximately 755 ft.
Use your calculator to find
√570,025