Divide the polynomials using the long division method.
what is the answer in the form P(x) = Q(x) - D(x) + R(x)
P(x) the dividend, Q(x) the quotient, R(x) the remainder ( i dont know what D(x) stands for
x+2 ) 3x^5 +5x^4 -4x^3 +2x^2 +7x +3
I think i got it
P(x) = 3x^5 +5x^4 -4x^3 +2x^2 +7x +3
Q(x) = -5
D(x) = x + 2
R(x) = 13
No, you didn't get it
First of all, your P(x) = Q(x) - D(x) + R(x)
makes no sense, should have been
P(x) = Q(x) x D(x) + R(x)
3x^5 +5x^4 -4x^3 +2x^2 +7x +3 ÷ (x+2)
......
(3x^5 +5x^4 -4x^3 +2x^2 +7x +3)
= (3x^4 - x^3 -2x^2 + 6x - 5)(x+2) + (13/x+2)
I will let you decide which expressions go with whichever ....
almost.
Q(x) is the quotient. It is 3x^4-x^2-2x^2+6x-5
That is,
3x^5 +5x^4 -4x^3 +2x^2 +7x +3 = (x+2)(3x^4-x^2-2x^2+6x-5)+13
-x^3, as in Reiny's answer. I missed my typo.
Ok for P(x) = Q(x) - D(x) + R(x)
do i replace the x's with the answers
like this which looks kinda weird:
P(3x^5 +5x^4 -4x^3 +2x^2 +7x +3)Q(3 x^4 - x^3 - 2 x^2 + 6 x - 5 )D(x + 2 )
R(13)
or is it supposed to be this way:
P(x) = 3x^5 +5x^4 -4x^3 +2x^2 +7x +3
Q(x) = 3 x^4 - x^3 - 2 x^2 + 6 x - 5
D(x) = x + 2
R(x) = 13