# math

what is a function that Contains no vertical asymptotes but has a hole at x=2 and
another function that contains a horizontal asymptote of 1, vertical asymptotes of 2 and -3, and a hole at x=4.

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1. For the first one, something like
y = (x-2)/(x^2 - 4) should do it

for the second, how about

y = x^2(x-4)/((x-2)(x+3)(x-4) )

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2. thank you

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3. no vertical asymptotes but has a hole at x=2
y = (x^2-2x)/(x-2)

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