so I'm factoring quadratics and this is the problem; 2x^2-50
you would multiply a(c) which would just give me -100 but I don't know what to do after this.
Since both terms are perfect squares, factor using the difference of squares formula, 2−b2=(a+b)(a−) where a=x and b=5 .
Remove unnecessary parentheses.2(x+5)(x−5)
2(x2−25)
Rewrite 25 as 5/2.
2(x2−5/2)
5/2= 5/2 as an exponent, the 2 is the exponent which should be floating over the five in the top right corner
Generally, we use ^ for exponents online
2x^2-50 = 2(x^2-25) = 2(x-5)(x+5)
To factor the quadratic expression 2x^2 - 50, you can first find the greatest common factor (GCF) of the coefficients. In this case, both 2 and -50 are divisible by 2, so you can factor out a 2:
2(x^2 - 25)
Now, you're left with the expression x^2 - 25, which is a difference of squares. To factor it further, you can rewrite it as:
(x)^2 - (5)^2
Now, you can recognize that this is a difference of squares pattern, which can be factored as:
(a^2 - b^2) = (a + b)(a - b)
Using this pattern, you can factor x^2 - 25 as:
(x + 5)(x - 5)
Therefore, the fully factored form of the quadratic expression 2x^2 - 50 is:
2(x - 5)(x + 5)