Constructing the locus of points which is always 5cm from the line.
Which line?
Looks like two parallel lines, one on either side of the given line
To construct the locus of points that are always 5 cm away from a given line, we will use the method of perpendicular bisectors. Here's how you can do it:
1. Start by drawing a straight line. Let's call this line "AB."
2. Take any point on the line and label it as "C." This will serve as a reference point.
3. From point C, measure a distance of 5 cm perpendicular to line AB on both sides. Mark these points as D and E.
4. Now, draw lines CD and CE, which are perpendicular to line AB and intersect line AB at points D and E, respectively.
5. With a compass, set the radius to 5 cm and place the pivot at point D. Draw an arc that intersects line CD. Let's call this point F.
6. Repeat step 5, but this time place the pivot at point E. Draw an arc that intersects line CE. Let's call this point G.
7. Connect points F and G to form a straight line segment.
8. The locus of points that are always 5 cm away from line AB will be the line segment FG. This means that any point on FG will always be 5 cm away from line AB.
By following these steps, you will have successfully constructed the locus of points that are always 5 cm away from the given line.