what is the mass of oxalic acid required to prepare 250cm3 of a 1.5M solution of the acid
How many mols do you need? That's mols = M x L = ?
Then mols = grams/molar mass. YOu know molar mass and mols solve for grams.
To calculate the mass of oxalic acid required to prepare a 1.5M solution in 250 cm3 of water, you need to know the molar mass of oxalic acid and use the formula:
Molarity (M) = moles of solute / volume of solution (L)
First, let's gather the necessary information:
1. Molarity (M) = 1.5M
2. Volume of solution = 250 cm3 (which needs to be converted to liters)
To convert the volume from cm3 to liters, we divide by 1000:
Volume of solution (L) = 250 cm3 / 1000 = 0.25 L
Next, rearrange the formula to solve for moles of solute:
moles of solute = Molarity × volume of solution
moles of solute = 1.5M × 0.25 L = 0.375 moles
Finally, to find the mass of oxalic acid required, we need to multiply the moles of solute by the molar mass of oxalic acid. The molar mass of oxalic acid is 90.03 g/mol.
Mass of oxalic acid = moles of solute × molar mass
Mass of oxalic acid = 0.375 moles × 90.03 g/mol ≈ 33.76 g
Therefore, approximately 33.76 grams of oxalic acid are required to prepare a 1.5M solution in 250 cm3 of water.