A father is 30 yrs old and his son is 5 yrs old. In how many years will the father be twice as old as the son?
5 x 2=10
30 - 10= 20
10 x 2=20
answer: 10 years
I think not.
Father = 30 + x
Son = 5 + x
so
30 + x = 2 (5+x)
30 + x = 10 + 2 x
x = 20 years
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30 + 20 = 50
5 + 20 = 25
sure enough, 50 = twice 25
yeah go with Damon's answer... sorry!!
To solve this problem, we need to set up an equation and solve for the number of years needed for the father's age to be twice the son's age.
Let's assume that it takes "x" number of years for the father's age to be twice the son's age.
Currently, the father is 30 years old, and the son is 5 years old. After "x" years, the father's age will be (30 + x) and the son's age will be (5 + x).
Setting up the equation:
(30 + x) = 2 * (5 + x)
Now, let's solve for "x".
30 + x = 10 + 2x
30 - 10 = 2x - x
20 = x
Therefore, it will take 20 years for the father to be twice as old as the son.