The sum of three consecutive whole numbers is 96.If the lowest number is y then:
a)write down an expression for the other two numbers in terms of y.
b)write down an equation involving y.
c)find y and hence find the other two numbers.
a) y+1 is the next number and the third number is y+2
b) y + (y+1) + (y+2) = 96 , that is the smallest plus the next plus the next :)
c) your turn to solve for y
step1:
y + y + 1 + y + 2 = 96
y + y + 1 + y + 2 = 96
y + y + y = 96-1-2
3y = 93
y= 93,3
y= 31
Is it correct?
3y = 93,
Y = 31.
post
To solve this problem, let's break it down step by step:
a) Write down an expression for the other two numbers in terms of y.
Since we have three consecutive whole numbers, we can represent them as y, y + 1, and y + 2. The lowest number is y, so the other two numbers can be expressed as y + 1 and y + 2.
b) Write down an equation involving y.
We know that the sum of the three consecutive numbers is 96, so we can create an equation using the expression from part a:
y + (y + 1) + (y + 2) = 96
c) Find y and hence find the other two numbers.
To solve the equation, combine like terms and simplify:
3y + 3 = 96
3y = 96 - 3
3y = 93
y = 93 / 3
y = 31
Now that we have found the value of y, which is 31, we can substitute it back into our expression from part a to find the other two numbers:
The other two numbers are y + 1 = 31 + 1 = 32, and y + 2 = 31 + 2 = 33.
Therefore, the lowest number is 31, and the other two numbers are 32 and 33.