circular (trigonometric) functions
 👍 0
 👎 0
 👁 114
Respond to this Question
Similar Questions

precalculus
What is the polar form of the equation 3x  4y = 12? The answer is r = 12/ (3cosx  4 sinx) (x = theta) I don't know how to get the answer though.
asked by Jamie on April 6, 2010 
Calc
Verify that the trigonometric equation is an identity. 1/2 sin 2 x − sin^2x over sinxcos2x = 1 over sinx+cosx Verify that the trigonometric equation is an identity. cotx over 1sinx =secx(cscx+1) Can someone please Help!!! these
asked by Ricky on April 20, 2017 
Maths  crazy maths question which involves graphi
This is a question that involves graphing although I'm not very good at it especially Trigonometric Functions >_< a) Find the equation of the tangent to the curve y = sinx at the origin For part (a) I've already found the equation
asked by Anonymous on July 20, 2008 
Math/Calculus
Please take a look at my work below and provide a good critique: Solve the differential equation using the method of undetermined coefficients or variation of parameters. y''  3y' + 2y = sin(x) yc(x)= c1*e^2x+c2*e^x
asked by COFFEE on July 11, 2007 
trig
Find the solutions to the equation cos2x=sinx and 2cos^2x3cosx3=0
asked by Jill on May 24, 2011 
Simplifying with Trigonometry Identities
Hi, I am a senior in High School having a really difficult time with two problems. I have to prove using the trigonometric identities that they equal each other but I am having a really hard time trying to get them to equal each
asked by amanda on March 7, 2007 
Trig Help
Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)] =[sinx+sin^2x]/[sinx+1] =[sinx+(1cos^2x)]/[sinx+1] =??? This is where I'm stuck. Can someone help me.
asked by Anonymous on March 11, 2012 
Trigonometry
Prove the following trigonometric identities. please give a detailed answer because I don't understand this at all. a. sin(x)tan(x)=cos(x)/cot^2 (x) b. (1+tanx)^2=sec^2 (x)+2tan(x) c. 1/sin(x) + 1/cos(x) = (cosx+sinx)(secx)(cscx)
asked by Jessy on November 24, 2013 
Trigonometic
Solving Trigonometic Equations solve for x and give the answers as a equations : ( by radian) 1)cos(sinx)=1 We know sin 2x = 2(sinx)(cosx) so (sinx)(cos)=1/2(sin 2x) So we can change your equation from (sinx)(cosx)=1 to 1/2(sin
asked by abdo on April 26, 2007 
Calculus
If y=3/(sinx+cosx) , find dy/dx A. 3sinx3cosx B. 3/(sinx+cosx)^2 C. 3/(sinx+cosx)^2 D. 3(cosxsinx)/(sinx+cosx)^2 E. 3(sinxcosx)/(1+2sinxcosx)
asked by Anonymous on March 14, 2015