A water tank can hold 56 5/7 litres of water. How much water is contained in the tank when it is 2/5 full?
56 5/7 = 397/5
397/5 * 2/5 = ?
What is the answer
To find how much water is contained in the tank when it is 2/5 full, we need to calculate a fraction of the total capacity of the tank.
First, let's calculate the total capacity of the tank. Given that it can hold 56 5/7 litres of water, we can convert this mixed number to an improper fraction. To do this, we multiply the whole number (56) by the denominator of the fraction (7) and then add the numerator (5). So:
56 x 7 = 392
392 + 5 = 397
The total capacity of the tank is 397/7 litres.
Next, we need to determine 2/5 of the total capacity. To do this, we multiply the total capacity of the tank by the fraction 2/5:
(397/7) x (2/5)
To multiply fractions, we multiply the numerators together and the denominators together. So:
(397 x 2) / (7 x 5)
This gives us:
794 / 35
Now, we need to simplify this fraction. Both the numerator and denominator are divisible by 2:
397 / 17
Therefore, when the tank is 2/5 full, there are 397/17 litres of water contained in the tank.