An airport X is due north of another airport Y.An aeroplane leaving X flies due south for 380km and airport y is now 50km away.How far is X from Y
380 + 50 (not there yet)
or
380 - 50 (flew right over it)
To find the distance between Airport X and Airport Y, we can use the Pythagorean Theorem as the given information forms a right triangle.
Let's denote:
- The distance between X and Y as "d".
- The distance that the airplane flew due south as "a" (380 km in this case).
- The distance from Y to the airplane's position after flying due south as "b" (50 km in this case).
According to the Pythagorean Theorem, in a right triangle:
c^2 = a^2 + b^2
In this case, c represents the distance between X and Y (d).
So, plugging in the given values:
d^2 = 380^2 + 50^2
Calculating the right side of the equation:
d^2 = 144400 + 2500
d^2 = 146900
Taking the square root of both sides to solve for d:
d = sqrt(146900)
d ≈ 383.08 km
Therefore, Airport X is approximately 383.08 km away from Airport Y.
XZ = 380km.
YZ = 50km.
XY + YZ = XZ,
XY + 50 = 380,