Hi, I am trying to do homework for my math 012 class- solving linear equations- and I need help with 9 of the problems. I would really appreciate any help with this. I can do the problems and send them to you, or however you prefer.
Thanks!
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ok thanks!
-6(1x-3)-26=-8
-6(1x-3)-26=-8
-6x+18-26=-8
-6x+44=-8
-44 -44
-6x=36
-6 =-6
x=6
It is conventional to just write x, instead of 1x, wheneve the coefficient of an algebraic variable is 1.
There is a mistake in what you did.
Let's take a look.
-6(x-3)-26 = -8
-6x +18 -26 = -8
(You got that far OK)
-6x - 8 = -8
-6x = 0
x = 0
One more thing with this problem if you can explain for me. how come in the forth step, it is -6x=0?
I added 8 to both sides of the equation, thus eliminating it.
how to solve this math problem x/3 - 8 = -2
Hello! I'd be happy to help you with your math homework. Please go ahead and send me the 9 linear equations that you need help with. To solve linear equations, we usually follow a step-by-step process. Here's a general guide you can use to solve linear equations:
1. Start by distributing any terms (if applicable).
- If there are parentheses in the equation, you can use the distributive property to multiply the term outside the parentheses by each term inside.
- Example: 2(x + 3) = 10 becomes 2x + 6 = 10 after distributing.
2. Combine like terms on both sides of the equation.
- Like terms are terms with the same variables raised to the same power.
- Example: 2x + 3x = 10 becomes 5x = 10 after combining like terms.
3. Isolate the variable term on one side of the equation.
- To do this, you need to get rid of any constants or any terms that do not include the variable you're solving for.
- Example: 5x = 10 becomes x = 10/5 or x = 2 after isolating the variable.
4. Check your solution.
- After finding a solution, substitute it back into the original equation to verify whether it satisfies the equation.
Once you've sent me the 9 linear equations, I'll guide you through the process of solving each one.