# math

Coin A is tossed three times and coin B is tossed two times. What is the probability that more heads are tossed using coin A than coin B?

THE ANSWER IS NOT 7/16

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1. Just counting the heads tossed,
P(3,2) = 1/8 * 1/4
P(3,1) = 1/8 * 1/2
P(3,0) = 1/8 * 1/4
P(2,1) = 3/8 * 1/2
P(2,0) = 3/8 * 1/4
P(1,0) = 3/8 * 1/4
P(A>B) = ∑P(A,B) = 1/2

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2. That is correct. Thanks.

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