Write an expression and then evaluate when x = -6.
Nine subtracted from the quotient of twice a number, x, and three.
twice a number, x
2x
quotient of ... and three
2x/3
nine subtracted from
2x/3 - 9
when x = -6
2(-6)/3 - 9 = -12/3 - 9 = -4-9 = -13
Not so hard when you take it step by step, right?
Oh ok Thx
I'll try to take it step by step but like i said thx
To write the expression, we will follow the order of operations (PEMDAS).
Step 1: Start with the given information: "twice a number, x, and three."
This is represented by the expression: 2x/3.
Step 2: Subtract nine from the quotient obtained in step 1.
The expression becomes: 2x/3 - 9.
To evaluate this expression when x = -6, substitute -6 for x in the expression.
Step 3: Replace x with -6 in the expression.
The new expression becomes: 2*(-6)/3 - 9.
Step 4: Simplify the expression.
Multiply: -12/3 - 9.
Divide: -4 - 9.
Subtract: -13.
Therefore, the value of the expression when x = -6 is -13.