the dimensional formula of m(dv /dt) is
(1) MLT-1
(2) M-1LT-1
(3) ML2T-1
(4) [MLT-2]
m dv/dt
=ma [dv/dt=a]
=mlt^-2
4 is the ans
4 is correct
M(dV/dT)=[M]×[(LT^-1)/(T)]=[M]×[LT^-1 × T^-1]=[MLT^-2]>>>>>>option d).
Well, let's break it down:
m represents mass, so it has the dimension M.
dv/dt represents the rate of change of velocity with respect to time, which has the dimension LT-1.
Now, let's multiply the dimensions together:
M × LT-1 = MLT-1
So, the dimensional formula of m(dv/dt) is (1) MLT-1.
Just remember, dimensions can be quite dimensional!
To determine the dimensional formula of m(dv/dt), where m represents mass, v represents velocity, and t represents time, we can break this down step by step:
1. The dimensional formula of mass (m) is [M].
2. The dimensional formula of velocity (v) is [LT-1].
3. The dimensional formula of time (t) is [T].
Now, let's substitute these values into the expression m(dv/dt):
m(dv/dt) = [M] * [(LT-1) / [T]]
When we simplify this expression, we get:
= [M] * [(L / T) * (T-1)]
= [MLT-1T-1]
Next, we simplify further:
= [MLT-2]
Therefore, the correct dimensional formula of m(dv/dt) is option (4) [MLT-2].