in the sequence 0.07,0.12,0.17,... what term has a value of 1.67?
like the 1st question , only different numbers
use the same technique
term value = 1st term + [difference * (term number - 1)]
To find the term with a value of 1.67 in the sequence 0.07, 0.12, 0.17, ..., we need to determine the pattern and then solve for the term.
Looking at the sequence, we can observe that each term is obtained by adding 0.05 to the previous term:
0.07 + 0.05 = 0.12
0.12 + 0.05 = 0.17
So, the sequence can be represented as an arithmetic progression with a common difference of 0.05.
To find the term that has a value of 1.67, we need to solve the equation:
0.07 + (n-1) * 0.05 = 1.67
Rearranging the equation, we have:
0.05n - 0.05 = 1.67 - 0.07
0.05n = 1.60
n = 1.60 / 0.05
n = 32
Therefore, the term with a value of 1.67 is the 32nd term in the sequence.
To find out which term in the sequence has a value of 1.67, we need to determine the pattern of the sequence and then plug in the value of 1.67 to find the corresponding term.
Looking at the given sequence 0.07, 0.12, 0.17, ..., we can observe that each term is obtained by adding 0.05 to the previous term.
To find the nth term of this sequence, we can use the formula:
nth term = first term + (n - 1) * common difference
In this case, the first term is 0.07 and the common difference is 0.05.
Let's substitute the value of the nth term and the corresponding value of 1.67 into the formula:
1.67 = 0.07 + (n - 1) * 0.05
Simplifying the equation:
1.67 = 0.07 + 0.05n - 0.05
1.67 - 0.07 + 0.05 = 0.05n
1.65 = 0.05n
Now, let's isolate n by dividing both sides of the equation by 0.05:
1.65 / 0.05 = n
33 = n
So, the term that has a value of 1.67 in the sequence is the 33rd term.