Simplify :1/1-cosx +1/1+cos x
Assuming : 1/(1-cosx) +1/(1+cos x)
= (1+cosx + 1-cosx)/((1-cosx)(1+cosx))
= 2/(1 - cos^2 x) <------ did you notice the difference of squares
using sin^2 x + cos^2 x = 1, I will let you take another step
To simplify the expression 1/(1-cos(x)) + 1/(1+cos(x)), we can start by finding a common denominator for the two fractions.
The common denominator would be (1-cos(x))(1+cos(x)).
Now, let's rewrite the expression with the common denominator:
1/(1-cos(x)) + 1/(1+cos(x)) = (1*(1+cos(x)) + 1*(1-cos(x))) / ((1-cos(x))(1+cos(x)))
Expanding the numerators:
= (1 + cos(x) + 1 - cos(x)) / ((1-cos(x))(1+cos(x)))
Simplifying the numerator:
= (2) / ((1-cos(x))(1+cos(x)))
Therefore, the simplified form of the expression 1/(1-cos(x)) + 1/(1+cos(x)) is 2/((1-cos(x))(1+cos(x))).