Math

A rectangular field is to be fenced in on four sides with a fifth piece of fencing placed Parallel to one of the shorter sides, so that the field is split in two parts. If 1600 m of fencing is available, find the largest possible area for this enclosure. What dimensions give this maximum area?

asked by Alex
  1. let the length be y m
    and each of the shorter pieces (the width) be x
    we know 2y + 3x = 1600
    y = 800 - 3x/2

    area = xy
    = x(800-3x/2)
    = 800x - 3x^2 /2

    find the first derivative, set it equal to zero and find x
    then find y, and the area xy

    posted by Reiny
  2. xmax is on the axis of symmetry of the parabola

    -b / 2a = -800 / (2 * -3/2) = 800 / 3

    posted by scott

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