The sides of the equilateral triangle is 3x+2,2y-x and y+3 find x and y.and the perimeter of the triangle
i didnt get it
3x+2 = 2y-x
3x+2 = y+3
Collect like terms
4x-2y = -2 ---eqn1
3x-y = 1 ---eqn2
Using elimination method
Multiply (eqn 2) by 2
6x-2y = 2 ---eqn3
4x -2y = -2 ---eqn2
_______________
2x = 4
Divide both sides by the coefficient of x
x = 2
Then substitute (2 for x) in eqn 3
6(2)-2y = 2
12-2y = 2
-2y = 2-12
-2y = -10
Divide both sides by -2
y = 5
P= a+b+c
3x+2 = 8cm
2y-x = 8cm
y+3 = 8cm
Perimeter= 24cm
That's the correct answer
I dont understand
2x-y=2
I am the one who ask the question
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i do not like the answer
I didn't understand the answer
well, since all the sides are the same length, we just have to solve
3x+2 = 2y-x
3x+2 = y+3
4x-2y = -2
3x-y = 1
Find x and y, and then you can find the perimeter.
I am not sure if the answers are correct.
3x+2cm=2y-x cm
3x+2cm=y+3cm
3x+2cm=2y-x cm
Collect like terms
3x+x cm - 2y=-2cm
4x cm+2y=-2cm...(i)
3x+2cm=y+3cm
Collect like terms
3x-y=3cm-2cm
3x-y=1cm...(ii)
4x cm+2y= -2cm
3x-y=1cm
Multiply eqn(i) by 3 and multiply eqn(ii) by 4
12x+6y= -6cm
—
12x-4y= 4cm
10y=-10cm
Divide both sides by 10
10y/10=-10cm/10
y=-1cm
Put -1cm in eqn(ii)
3x-y=1cm
3x-(-1cm)=1cm
3x+1=1cm
Collect like terms
3x=1-1
3x=0
Divide both sides by 3
3x/3=3/3
x=0
So, x=0 and y=-1
Perimeter of the triangle=
(3x+2cm) + (2y-x)cm + (y+3cm)
=3(0)+2 + 2(-1)-0 + (-1)+3
=0+2 + (-2) + 2
=2-2+2
=2
That is my perimeter answer. Not sure if it's correct.