let's suppose a lies along the x-axis, and that 3a-2b makes an angle of θ with a. Then
|-2b|^2 = |3a|^2 + |3a-2b|^2 - 2*|3a|*|3a-2b|*cosθ
100 = 576+400-2*24*20cosθ
Then |-2b| makes an angle of 125.1° with |3a|
The components of -2b are thus (-5.75,8.18)
So, b=(2.87,-4.09) and a=(8,0)
and a+b = (10.87,-4.09)
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