What happens if I don’t do well on the accuplacer test? I suck at math.
If I score low on math will they give me a remedial/low level math course?
That depends upon the college. Ask a counselor at that college.
The table shows the results of spinning a four-colored spinner 50 times. Find the experimental probability and express it as a decimal.
P(not red) = ?
Color | red | blue | green | yellow
# of | 20 | 10. | 9 | 11
Times
Spun
A. 0.6
B. 0.4
C. 0.2
D. 0.3
P(not red) = P(blue) + P(green) + P(yellow)
P(not red) = (10 + 9 + 11) / 50
P(not red) = 30 / 50
P(not red) = 0.6
Therefore, the answer is A. 0.6.
You roll a number cube 20 times. The number 4 is rolled 8 times. What is the experimental probability of rolling a 4?
A. 40%
B. 25%
C. 20%
D. 17%
Experimental probability of an event happening is equal to:
(number of times the event occurs) / (total number of trials)
In this case, the event is rolling a 4 and the total number of trials is 20.
Experimental probability of rolling a 4 = 8/20 = 0.4
Converting 0.4 to a percentage: 0.4 x 100 = 40%
Therefore, the answer is A. 40%.
The table below shows the results of flipping two coins. How does the experimental probability of getting at least one tails compare to the theoretical probability of getting at least one tails
Outcome | HH | HT | TH | TT |
Numbers | 28 | 22 | 34 | 16
Of times
Tossed
A. The experimental probability is 3% greater than the theoretical probability.
B. The theoretical probability is 3% greater than the experimental probability.
C. The experimental probability is equal to the theoretical probability.
D. The experimental probability is about 1% less than the theoretical probability.
The theoretical probability of getting at least one tails on flipping two coins can be found using the probability of the complement event, i.e. getting no tails on two flips:
P(no tails) = P(both heads) = 1/4
P(at least one tails) = 1 - P(no tails) = 1 - 1/4 = 3/4
The experimental probability of getting at least one tails can be found by adding up the frequencies of getting at least one tails:
Experimental probability of getting at least one tails = (22 + 34 + 16) / 100 = 0.72
Comparing the experimental and theoretical probabilities, we get:
Difference = |Experimental probability - Theoretical probability| * 100 %
Difference = |0.72 - 0.75| * 100 % = 3%
Therefore, the answer is A. The experimental probability is 3% greater than the theoretical probability.
The probability of winning a game is 15%. If you play 20 times, how many times should you expect to win?
A. 5 times
B. 3 times
C. 6 times
D. 15 times
The expected number of wins can be found by multiplying the probability of winning by the number of times played:
Expected number of wins = Probability of winning x Number of times played
Expected number of wins = 0.15 x 20
Expected number of wins = 3
Therefore, the answer is B. 3 times.
The probability of having a winning raffle ticket is 20%. If you bought 50 tickets, how many winning tickets should you expect to have?
A. 3 tickets
B. 8 tickets
C. 10 tickets
The expected number of winning tickets is equal to the probability of winning multiplied by the total number of tickets purchased:
Expected number of winning tickets = Probability of winning x Total number of tickets purchased
Expected number of winning tickets = 0.20 x 50
Expected number of winning tickets = 10
Therefore, the answer is C. 10 tickets.
A company rinds a detective toys in a sample of 600. Predict now many detective toys are in a shipment of 24,000.
A. 40 toys
B. 166 toys
C. 200 toys
D. 20 toys
Assuming that the proportion of detective toys in the shipment is the same as in the sample, we can use proportions to solve for the number of detective toys in the shipment:
number of detective toys in sample / sample size = number of detective toys in shipment / shipment size
Simplifying this formula by cross-multiplication, we get:
number of detective toys in shipment = (number of detective toys in sample / sample size) x shipment size
number of detective toys in shipment = (600 / 600) x 24,000
number of detective toys in shipment = 24,000
Therefore, the answer is not one of the answer choices provided. The predicted number of detective toys in the shipment is 24,000.
Which of the following is an example of independent events?
A. rolling two number cubes
B. selecting marbles from a bag without replacement after each draw
C. choosing and eating a piece of candy from a dish and then choosing another piece of candy
D. Pulling a card from a deck when other players have already pulled several cards from that deck
The correct choice is D. Pulling a card from a deck when other players have already pulled several cards from that deck.
Independent events are those where the outcome of one event does not affect the probability of the other event. In this case, other players drawing several cards from the deck does not affect the probability of the next player drawing a specific card.
In options A, B, and C, the outcomes of the first event affect the probability of the second event, making them dependent events.
A bag of fruit contains 4 apples, 1 plum, 2 apricots, and 3 oranges. Pieces of fruit are drawn ( twice with replacement. What is P(apple, then apricot)?
A. 4/5
B. 2/25
C. 3/25
D. 3/5
The probability of drawing one apple from the bag is 4/10, or 2/5, since there are 4 apples out of a total of 10 pieces of fruit. Drawing a second apple with replacement is also 2/5. The probability of drawing an apricot from the remaining pieces of fruit after drawing two apples is 2/8, or 1/4, since there are 2 apricots out of a total of 8 pieces of fruit left.
To find the probability of drawing an apple and then an apricot with replacement, we multiply the probabilities of the two events:
P(apple, then apricot) = P(apple) x P(apricot after drawing an apple)
P(apple, then apricot) = (2/5) x (1/4)
P(apple, then apricot) = 2/20
P(apple, then apricot) = 1/10
Therefore, the answer is not one of the answer choices provided. The correct answer is 1/10.
A coin is flipped three times. How the does P(H, H, H) compare to P(H, T, H)?
A. P(H, H, H) is greater than P(H, I, H).
B. P(H, T, H) is greater than P(H, H, H).
C. The probabilities are the same.
D. There is no way to tell with the information given
The coin flip is an independent event, which means that the outcome of one flip does not affect the outcome of another flip. Therefore, the probability of getting a head on any single flip is 1/2, and the probability of getting a tail on any single flip is also 1/2.
To find the probability of a specific sequence of coin flips, we multiply the probabilities of each individual flip.
P(H, H, H) = (1/2) x (1/2) x (1/2) = 1/8
P(H, T, H) = (1/2) x (1/2) x (1/2) = 1/8
Since both probabilities are the same, the answer is C. The probabilities are the same.
A coin is tossed and a number cube is rolled. What is P(heads, a number less than 5)?
A. 1/3
B. 5/12
C. 2/3
D. 5/6
The probability of getting heads on a toss of a coin is 1/2. The probability of getting a number less than 5 on a roll of a number cube is 4/6, or 2/3, since there are four numbers less than 5 (1, 2, 3, and 4) out of a total of six possible outcomes.
To find the probability of both events occurring together, we multiply their probabilities:
P(heads, a number less than 5) = P(heads) x P(a number less than 5)
P(heads, a number less than 5) = (1/2) x (2/3)
P(heads, a number less than 5) = 1/3
Therefore, the answer is A. 1/3.