Math

Rewrite in rectangular form: r=6 cos theta
I got (x-3)^2+y^2=6

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  1. You almost had it.

    r=6 cos Ø
    recall that cosØ = x/r

    r = 6x/r
    r^2 = 6x , recall that r^2 = x^2 + y^2
    x^2 + y^2 = 6x
    x^2 - 6x + 9 + y^2 = 9
    (x-3)^2 + y^2 = 9

    check:
    polar plot: http://www.wolframalpha.com/input/?i=polar+plot+r%3D6+cos+%C3%98
    cartesian plot: http://www.wolframalpha.com/input/?i=plot+(x-3)%5E2+%2B+y%5E2+%3D+9

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  2. Thank you :)

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