# Math

What are the solution of the system?
y=x^2+3x-4
y=3x+2

A (-3,6) and (2,-4)
B(-3,-4) and (2,6)
C (-3,-4) and (-2,-2)
D no solution

I think it is D

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1. x^2+3x-4 = 3x+2
x^2 = 6
x = ±√6
If x = √6 , y = 3√6 + 2
if x = -√6 , y = -3√6 + 2

none of the choices given are correct, do you have a typo?

http://www.wolframalpha.com/input/?i=solve++y%3Dx%5E2%2B3x-4+,+y%3D3x%2B2

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2. 3x+2 = x^2+3x-4
x^2 - 6 = 0
x = +/- sqrt 6
if +sqrt 6
y = 3sqrt 6 + 2 = 6+3sqrt 6 -4 check :)
there are solutions but none of them are on your list

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