# physics

It takes 5.28 J of work to stretch a Hookes Laq spring 9.82 cm from its unstressed length. How much extra work is required to stretch an additional 11.9 cm? anwser in J

Figure the Potential energy at 11.9, and at 9.82cm. The difference is the energy that stretched the spring.

Or, the calculus way..

Work= INT kxdx from .0982 to .119 m

i have nooooooooo clue sowwie

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