Calculate the weight of 6.022*10^23 molecules of caco3.
it's one mole
So, add up the atomic weights of all the atoms, and that's how many grams of CaCO3 there are.
To calculate the weight of 6.022 * 10^23 molecules of CaCO3, you need to know the molar mass of CaCO3 and use Avogadro's number.
Let's break it down step by step:
Step 1: Determine the molar mass of CaCO3.
To do this, you'll need to calculate the atomic mass of each element in CaCO3 and sum them up.
- The atomic mass of Ca (calcium) is approximately 40.08 g/mol.
- The atomic mass of C (carbon) is approximately 12.01 g/mol.
- The atomic mass of O (oxygen) is approximately 16.00 g/mol.
Now, multiply each atomic mass by the number of atoms in each element within one molecule of CaCO3 and sum them up:
Molar mass of CaCO3 = (1 * 40.08) + (1 * 12.01) + (3 * 16.00)
Step 2: Use Avogadro's number.
Avogadro's number (6.022 * 10^23) represents the number of particles (atoms, ions, or molecules) in one mole of a substance. In this case, it tells us the number of molecules in question.
So, multiply Avogadro's number by the molar mass of CaCO3 to get the weight:
Weight of 6.022 * 10^23 molecules of CaCO3 = (6.022 * 10^23) * (molar mass of CaCO3 in g/mol)
By following these steps, you should be able to calculate the weight of 6.022 * 10^23 molecules of CaCO3.